Time, Work, Efficiency & Pipes-Cisterns Quiz | Quantitative Aptitude MCQ Practice for IBPS AFO 2026

1

A, B and C can complete a work alone in 20, 24 and 30 days respectively. They start working together. After 2 days, A leaves the work. Two days after A leaves, C also leaves the work. In how many days is the work completed?

Solution & Explanation LCM(20, 24, 30) = 120 units (total work). Efficiency: A = 6, B = 5, C = 4 units/day. Days 1−2 (A+B+C): work done = (6+5+4) × 2 = 30 units. Days 3−4 (B+C only): work done = (5+4) × 2 = 18 units. Total = 48 units. Remaining = 120 − 48 = 72 units. Only B works at 5 units/day. Days needed = 72/5 = 14.4 days. Total = 2 + 2 + 14.4 = 18.4 days. Hence option A is correct.

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2

A, B and C together can complete a piece of work in 12 days. B alone can complete it in 30 days and C alone in 40 days. In how many days can A alone complete the work?

Solution & Explanation Combined rate of A, B and C = 1/12. B's rate = 1/30 and C's rate = 1/40, so B+C's rate = 7/120. A's rate = 1/12 − 7/120 = 3/120 = 1/40. Therefore, A alone takes 40 days.

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3

A pump can be used for filling as well as emptying a tank. The capacity of the tank is 3000 m³. The emptying capacity of the tank is 15 m³ per minute higher than its filling capacity, and the pump needs 10 minutes less to empty the tank than it needs to fill it. What is the emptying capacity of the tank?

Solution & Explanation Let filling capacity = f m³/min, emptying = f+15. 3000/f − 3000/(f+15) = 10 ⇒ 3000×15 = 10f(f+15) ⇒ f²+15f−4500=0 ⇒ f=60 (taking the positive root). Emptying capacity = 60+15 = 75 m³/min.

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4

A man works thrice as fast as a woman. A woman works thrice as fast as a boy. If 15 men can complete a work in 18 days, how many days would be required by 44 women and 30 boys together to complete the same work?

Solution & Explanation Let one boy's efficiency = 1 unit. Then one woman = 3 units and one man = 9 units. Total work = 15 × 9 × 18 = 2430 units. Efficiency of 44 women and 30 boys = (44 × 3) + 30 = 162 units/day. Time = 2430/162 = 15 days.

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5

A alone can complete a work in 18 days and B alone in 24 days. They worked together for 6 days, after which B left. C then joined A and the remaining work was completed in 5 more days. In how many days can C alone complete the work?

Solution & Explanation

Solution:

A+B per day = 1/18 + 1/24 = 4/72 + 3/72 = 7/72.

Work done in 6 days = 6 × 7/72 = 7/12.

Remaining work = 1 − 7/12 = 5/12.

A+C complete 5/12 work in 5 days → rate = 5/12 ÷ 5 = 1/12 per day.

C's rate = 1/12 − 1/18 = 3/36 − 2/36 = 1/36.

C alone = 36 days.

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Time, Work, Efficiency & Pipes-Cisterns Quiz for IBPS AFO 2026

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