Time, Work, Efficiency & Pipes-Cisterns Quiz | Quantitative Aptitude MCQ Practice for IBPS AFO 2026

1

A pump can be used for filling as well as emptying a tank. The capacity of the tank is 3000 m³. The emptying capacity of the tank is 15 m³ per minute higher than its filling capacity, and the pump needs 10 minutes less to empty the tank than it needs to fill it. What is the emptying capacity of the tank?

Solution & Explanation Let filling capacity = f m³/min, emptying = f+15. 3000/f − 3000/(f+15) = 10 ⇒ 3000×15 = 10f(f+15) ⇒ f²+15f−4500=0 ⇒ f=60 (taking the positive root). Emptying capacity = 60+15 = 75 m³/min.

1 / 5

2

A, B and C together can complete a piece of work in 12 days. B alone can complete it in 30 days and C alone in 40 days. In how many days can A alone complete the work?

Solution & Explanation Combined rate of A, B and C = 1/12. B's rate = 1/30 and C's rate = 1/40, so B+C's rate = 7/120. A's rate = 1/12 − 7/120 = 3/120 = 1/40. Therefore, A alone takes 40 days.

2 / 5

3

A is 20% more efficient than B who is 25% more efficient than C. If A at his 40% efficiency can complete a work in 60 days, then in how many days will B and C together complete the work?

Solution & Explanation Let C's efficiency = 100 units. Then B = 125 and A = 150. A works at 40% efficiency, so effective efficiency = 60. Total work = 60 × 60 = 3600 units. B + C = 225 units/day. Time = 3600/225 = 16 days.

3 / 5

4

Two pipes A and B can fill a tank in 24 minutes and 32 minutes respectively. Both pipes are opened together, but pipe A is closed after some time, and pipe B continues until the tank is completely filled in a total of 18 minutes. For how long was pipe A open?

Solution & Explanation Let pipe A be open for t minutes; pipe B runs for the entire 18 minutes. t/24 + 18/32 = 1 ⇒ t/24 = 1 − 9/16 = 7/16 ⇒ t = 24 × 7/16 = 10.5 minutes = 10 min 30 sec.

4 / 5

5

A alone can do a work in 20 days. B is 125% more efficient than A. A and B started working together and worked for 4 days. C alone completed the remaining job in 22 days. How many days would C alone take to complete the entire job?

Solution & Explanation B's efficiency = 1.25 × A's efficiency (i.e. B's rate = 1.25/20 = 1/16 per day). Combined (A+B) rate = 1/20+1/16 = 9/80 per day. In 4 days: 4×9/80 = 9/20 of work done; remaining = 11/20. C completes 11/20 in 22 days, so C's rate = (11/20)/22 = 1/40 per day ⇒ C alone takes 40 days.

5 / 5

Time, Work, Efficiency & Pipes-Cisterns Quiz for IBPS AFO 2026

Elevate Your Learning.