Average & Problems on Ages Quiz | Quantitative Aptitude MCQ Practice for IBPS AFO 2026

1

Ratio of present age of A to B is 8:5 and average of B and C is 35 years. If five years ago sum of A and B was 55, find difference between present age of A and C.

Solution & Explanation (8x-5)+(5x-5)=55 => 13x=65 => x=5. A=40, B=25. Avg(B,C)=35 => C=45. Diff(A,C) = |40-45| = 5.

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2

The average of 6 numbers is 20. If one number is removed, the average becomes 15. What is the number removed?

Solution & Explanation The sum of 6 numbers is 6 * 20 = 120. When one number is removed, there are 5 numbers left, and their average is 15. So, the sum of these 5 numbers is 5 * 15 = 75. The removed number is the difference between the initial sum and the new sum, which is 120 - 75 = 45.

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3

The average of 12 results is 15 and average of first two is 14. What is average of remaining ten?

Solution & Explanation Total = 12 × 15 = 180. First two = 2 × 14 = 28. Remaining = 180 - 28 = 152. Average = 152 ÷ 10 = 15.2.

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4

Sum of Ravi’s and Shivam’s age 4 years ago was 80. Ravi’s age 14 years ago equals Shivam’s age 4 years ago. Find Ravi’s present age.

Solution & Explanation (R-4)+(S-4)=80 => R+S=88. R-14=S-4 => R-S=10. Adding: 2R=98 => R=49.

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5

Three years ago average age of Amit, Bittu and Chitu was 27. Four years hence ratio of Amit and Chitu is 7:10. Bittu is 6 years younger than Chitu. Find present age of Amit.

Solution & Explanation Three years ago total = 27×3 = 81; Four years hence total = 102; Let ages = 7x, 10x, 10x−6; 27x=108; x=4; Amit present age = 28−4 = 24

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Average & Problems on Ages Quiz for IBPS AFO 2026

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