Boats & Streams Quiz | Quantitative Aptitude MCQ Practice for IBPS AFO 2026

1

Find the ratio of the speeds of the train and the speed of dog.

Solution & Explanation Let the length of the tunnel be L. Dog's position from P = 5L/11, so from Q = 6L/11. Let the train's speed be T and the dog's speed be D. Time taken by dog to cover 5L/11 = Time taken by train to reach P. Time taken by dog to cover 6L/11 = Time taken by train to reach Q. Ratio of speeds of train and dog is 11:1.

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2

A swimmer swims downstream at 11 km/h and upstream at 5 km/h. Find the speed of the current.

Solution & Explanation Current speed = (11 − 5) ÷ 2 = 3 km/h.

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3

Ratio of upstream speed to that of downstream speed is 3:5. If speed of boat in still water is 24 km/hr then in how much time boat will cover 36 km in upstream and 60 km in downstream together?

Solution & Explanation Upstream/Downstream = 3/5. Boat = 4x = 24 => x=6. Upstream = 18, Downstream = 30. Time = 36/18 + 60/30 = 2 + 2 = 4.

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4

A boat travels 84 km downstream and 60 km upstream in a total of 12 hours. If the speed of the stream is 2 km/h, how long will the boat take to travel 96 km in still water?

Solution & Explanation

Solution:

Let speed of boat in still water = b km/h. Stream speed = 2 km/h.

Downstream speed = b + 2, Upstream speed = b − 2.

84/(b+2) + 60/(b−2) = 12

84(b−2) + 60(b+2) = 12(b+2)(b−2)

84b − 168 + 60b + 120 = 12(b²−4)

144b − 48 = 12b² − 48 → 12b² − 144b = 0 → b(b−12) = 0 → b = 12 km/h.

Time for 96 km in still water = 96 ÷ 12 = 8 hours.

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5

First train starts from station A at 6 am and reaches station B at 4 pm and second train started from B at 7 am and reaches A at 3 pm. Then, find the time at which both the trains meet each other.

Solution & Explanation First train (A to B): 6 am to 4 pm is 10 hours. Second train (B to A): 7 am to 3 pm is 8 hours. Let the distance between A and B be D. Speed of first train = D/10. Speed of second train = D/8. The first train starts at 6 am, and the second at 7 am. In the first hour (6 am to 7 am), the first train covers (D/10) * 1 = D/10 distance. The remaining distance is D - D/10 = 9D/10. Now, both trains are moving towards each other from 7 am. Their relative speed = D/10 + D/8 = (4D + 5D)/40 = 9D/40. Time to meet = Remaining Distance / Relative Speed = (9D/10) / (9D/40) = (9D/10) * (40/9D) = 4 hours. Since they start moving towards each other from 7 am, they will meet at 7 am + 4 hours = 11:00 am.

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Boats & Streams Quiz for IBPS AFO 2026

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