Time, Speed & Distance Quiz | Quantitative Aptitude MCQ Practice for IBPS AFO 2026

1

A person travels from X to Y at a constant speed. If his speed was increased by 10 km/hour, it would have taken one hour lesser to cover the distance. It would have taken further 45 minutes lesser if the speed was further increased by 10 km/h. Find the distance between X and Y.

Solution & Explanation Let speed = v, distance = D. D/(v+10) = D/v − 1 → D = v(v+10)/10 ... (i). D/(v+20) = D/v − 1.75 → D = 7v(v+20)/80 ... (ii). Equating: v(v+10)/10 = 7v(v+20)/80 → 8(v+10) = 7(v+20) → v = 60 km/h. D = 60×70/10 = 420 km. Answer: E.

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2

A train crosses a platform of length 240 m in 24 seconds and crosses a pole in 8 seconds. Find the length of the train.

Solution & Explanation Let the length of the train = L. Speed = L/8. Time to cross the platform = (L+240)/24 = L/8. Solving, 8(L+240) = 24L ⇒ 8L + 1920 = 24L ⇒ 16L = 1920 ⇒ L = 120 m.

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3

Two trains having length 90 m and 110 m are running on parallel track in the same direction with smaller train running at a speed of 45 km/h. The train having length 110 m crosses a man in the smaller train in 18 s. Find the speed of the longer train.

Solution & Explanation Crossing a man in the other train: only the length of the crossing train matters = 110 m. Relative speed = 110/18 m/s = 55/9 m/s = 55/9 × 18/5 km/h = 22 km/h. Same direction → longer train speed = 45+22 = 67 km/h. Answer: A.

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4

The speed of a car is 1.5 times the speed of a bus. If the speed of the car is 60 km/hr then what will be the difference in the time taken by the bus and the time taken by the car to cover a distance of 720 km?

Solution & Explanation Car speed = 60 km/h. Bus speed = 60/1.5 = 40 km/h. Car time = 720/60 = 12 h. Bus time = 720/40 = 18 h. Difference = 6 h. Answer: A.

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5

A train running at 35 m/s crosses a pole in 12 seconds and also crosses another train of length 400 m running in the same direction in 41 seconds. If the speed of the second train is increased by 40%, find the time taken by it to cross a platform of 230 m.

Solution & Explanation Length of first train = 35 × 12 = 420 m. Relative speed = (420 + 400)/41 = 20 m/s. Speed of second train = 35 − 20 = 15 m/s. Increased speed = 21 m/s. Time to cross platform = (400 + 230)/21 = 30 sec.

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Time, Speed & Distance Quiz for IBPS AFO 2026

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