Time, Work, Efficiency & Pipes-Cisterns Quiz | Quantitative Aptitude MCQ Practice for IBPS AFO 2026

1

Two pipes A and B can fill a tank in 24 minutes and 32 minutes respectively. Both pipes are opened together, but pipe A is closed after some time, and pipe B continues until the tank is completely filled in a total of 18 minutes. For how long was pipe A open?

Solution & Explanation Let pipe A be open for t minutes; pipe B runs for the entire 18 minutes. t/24 + 18/32 = 1 ⇒ t/24 = 1 − 9/16 = 7/16 ⇒ t = 24 × 7/16 = 10.5 minutes = 10 min 30 sec.

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2

A man works thrice as fast as a woman. A woman works thrice as fast as a boy. If 15 men can complete a work in 18 days, how many days would be required by 44 women and 30 boys together to complete the same work?

Solution & Explanation Let one boy's efficiency = 1 unit. Then one woman = 3 units and one man = 9 units. Total work = 15 × 9 × 18 = 2430 units. Efficiency of 44 women and 30 boys = (44 × 3) + 30 = 162 units/day. Time = 2430/162 = 15 days.

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3

The work done by 5 boys in 20 days is equal to the work done by 10 men in 8 days. Four men and four boys together undertake a work and complete it in 3 days for Rs. 540. Find the amount earned by the boys for their total contribution.

Solution & Explanation

Solution:

Given, the work done by 5 boys in 20 days equals the work done by 10 men in 8 days.

Therefore,

5 × 20 × B = 10 × 8 × M

100B = 80M ⇒ 5B = 4M

Hence, 4 men = 5 boys.

In the given team:

4 men = 5 boys
4 boys = 4 boys

Total equivalent work = 9 boys.

Boys' contribution = 4/9 of the total work.

Boys' wages = 540 × (4/9) = Rs. 240.

Answer = Rs. 240.

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4

In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.
Quantity A: A can do a piece of work in 10 days and B can do the same work in 15 days. They start working together and after 4 days, A left the work. Find in how many days the total work will be completed.
Quantity B: P can do a piece of work in 15 days and Q can do the same work in 25 days. They start working together and after 5 days, Q left the work. Find in how many days the remaining work will be completed.

Quantity A = Quantity B or No relation

Quantity A ≥ Quantity B

Quantity A < Quantity B

Quantity A > Quantity B

Quantity A ≤ Quantity B

Solution & Explanation A: Combined rate = 1/10+1/15 = 1/6. Work in 4 days = 4/6 = 2/3. Remaining = 1/3. B alone: (1/3)÷(1/15) = 5 days. Total = 4+5 = 9 days. B: Combined rate = 1/15+1/25 = 8/75. Work in 5 days = 40/75 = 8/15. Remaining = 7/15. P alone: (7/15)÷(1/15) = 7 days. A (9 days) > B (7 days). Answer: D.

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5

A alone can complete a work in 18 days and B alone in 24 days. They worked together for 6 days, after which B left. C then joined A and the remaining work was completed in 5 more days. In how many days can C alone complete the work?

Solution & Explanation

Solution:

A+B per day = 1/18 + 1/24 = 4/72 + 3/72 = 7/72.

Work done in 6 days = 6 × 7/72 = 7/12.

Remaining work = 1 − 7/12 = 5/12.

A+C complete 5/12 work in 5 days → rate = 5/12 ÷ 5 = 1/12 per day.

C's rate = 1/12 − 1/18 = 3/36 − 2/36 = 1/36.

C alone = 36 days.

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Time, Work, Efficiency & Pipes-Cisterns Quiz for IBPS AFO 2026

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